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secondary 4 | Physics
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Help Adhvika! Anyone can contribute an answer, even non-tutors.
how to do thus question? Please explain. Thanks!
Date Posted: 5 years ago
Views: 386
(b) looks correct.
As the ball rolls down the slope, its speed increases. In turn, the kinetic energy increases quadratically (since KE = 0.5 mv2). Since the total energy of the ball remains conserved, the PE will decrease in a manner similar to the increase of the KE to maintain the energy balance.
As the ball rolls down the slope, its speed increases. In turn, the kinetic energy increases quadratically (since KE = 0.5 mv2). Since the total energy of the ball remains conserved, the PE will decrease in a manner similar to the increase of the KE to maintain the energy balance.
Since its a smooth/frictionless slope, no energy is loss due to work done against friction. Hence the total energy remains the same, so the rate of loss of KE = rate of gain of GPE, by the Principle of Conservation of Energy. Hence A is the best answer.
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