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secondary 4 | A Maths
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10(iii)
Date Posted: 5 years ago
Views: 205
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We choose the boundary conditions at x = 0 and x = pi to form two points to start a line.
Date Posted:
5 years ago
And make sure you draw the other graph first because this line is to be drawn over the other graph.
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Something like this. The original unmodulused sine graph peaks at 2, and this will remain on the graph. For the straight line, it starts at (0, 2) which is at the same height as this peak. There will be a total of 4 intersections, so 4 solutions altogether.
Date Posted:
5 years ago
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