No, ABC is not 116 degrees

why？

The ‘angle at centre is twice the angle at circumference’ rule does not work this way.

ohh ...then how to calculate for x？

Will do the full working when I have time.

....ok can asap

EOD = 2 x ECD (angle at centre = 2 x angle at circumference)

58° = 2 x ECD
ECD = 58° ÷ 2 = 29°

ABCE is a cyclic quadrilateral.

So EAB + ECB = 180° (opposite angles of a cyclic quadrilateral add up to 180)

ECB = 180° - 100° = 80°

x = ECD + ECB = 80° + 29° = 109°

And follow up with the EABC cyclic quadrant.

Since EAB is 100 deg, ECB is 180 - 100 = 80 deg.

Add this to J’s answer.

EDIT: J has since included this 80 degrees. Final answer is 109 degrees.