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Secondary 1 | Maths

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Did i factorise correctly? I would be grateful if u could help me.

(a - b)⁻ⁿ⁺² / (a - b)⁻ⁿ⁻¹

= (a - b)⁻ⁿ⁺² / [ (a - b)⁻ⁿ/(a - b) ]

= (a - b)² / [ 1/(a - b) ]

= (a - b)² x (a - b)

= (a - b)³

(1 - c)³/(1 - c)

= (1 - c)²

hence,

[25(a-b)⁻ⁿ⁺²(1 - c)³ / 15(a-b)⁻ⁿ⁻¹(1 - c) ]

= [5(a - b)³ (1 - c)²]/3

I doubt powers -n + 2 and -n - 1 should be seen in Sec 1 though.

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