## Ask Singapore Homework?

Upload a photo of a Singapore homework and someone will email you the solution for free.

## Question

Secondary 1 | Maths
One Answer Below

Anyone can contribute an answer, even non-tutors.

##### Moonkake

chevron_right chevron_right

Did i factorise correctly? I would be grateful if u could help me.

Date Posted: 1 month ago
Views: 19
Snell
1 month ago
25/15 = 5/3

(a - b)⁻ⁿ⁺² / (a - b)⁻ⁿ⁻¹
= (a - b)⁻ⁿ⁺² / [ (a - b)⁻ⁿ/(a - b) ]
= (a - b)² / [ 1/(a - b) ]
= (a - b)² x (a - b)
= (a - b)³

(1 - c)³/(1 - c)
= (1 - c)²

hence,
[25(a-b)⁻ⁿ⁺²(1 - c)³ / 15(a-b)⁻ⁿ⁻¹(1 - c) ]
= [5(a - b)³ (1 - c)²]/3
Moonkake
1 month ago
Thanku i understand where i went wrong
Eric Nicholas K
1 month ago
Full treatment of the concept is seen in Sec 3 A/E Maths under the chapter 'Indices'.

I doubt powers -n + 2 and -n - 1 should be seen in Sec 1 though.

### See 1 Answer

done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
##### Arnold K H Tan's answer
835 answers (A Helpful Person)
1st
You will need to use laws of indices to solve this, typically taught in Secondary 3.
Date Posted: 1 month ago