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primary 5 | Maths
| Area & Volume
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Help Vic! Anyone can contribute an answer, even non-tutors.
Please help, thanks
Date Posted: 5 years ago
Views: 561
PA is twice of TB.
Since they have the same base length , area of RPQ is twice of RTQ.
RPQ = 2 x 34cm² = 68cm²
SC is thrice of TB.
Since they have the same base length , area of RSQ is thrice of RTQ.
RSQ = 3 x 34cm² = 102cm²
Realise that RSQ and RPQ overlap . The overlapping part is RTQ.
If you add RSQ and RPQ together to find the area of the whole figure, you would have double counted RTQ.
So area of figure = RSQ + RPQ - RTQ
Since they have the same base length , area of RPQ is twice of RTQ.
RPQ = 2 x 34cm² = 68cm²
SC is thrice of TB.
Since they have the same base length , area of RSQ is thrice of RTQ.
RSQ = 3 x 34cm² = 102cm²
Realise that RSQ and RPQ overlap . The overlapping part is RTQ.
If you add RSQ and RPQ together to find the area of the whole figure, you would have double counted RTQ.
So area of figure = RSQ + RPQ - RTQ
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