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secondary 3 | A Maths
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hi i need help in this qn !! plis try to ans asap thanks
Date Posted: 5 years ago
Views: 241
2^(2x) × 2³ × 7^x × 7^(-2) = 2^(3x) × (7²)^x
2^(2x) × 8 × 7^x × ¹/7² = 2^(3x) × 7^(2x)
8 × 1/49 = 2^(3x) × 7^(2x) ÷ 2^(2x) ÷ 7^x
8/49 = 2^(3x - 2x) × 7^(2x - x)
8/49 = 2^x × 7^x
8/49 = (2 x 7)^x
8/49 = 14^x
2^(2x) × 8 × 7^x × ¹/7² = 2^(3x) × 7^(2x)
8 × 1/49 = 2^(3x) × 7^(2x) ÷ 2^(2x) ÷ 7^x
8/49 = 2^(3x - 2x) × 7^(2x - x)
8/49 = 2^x × 7^x
8/49 = (2 x 7)^x
8/49 = 14^x
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done
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Another method of approach for your consideration.
Date Posted:
5 years ago
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