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primary 6 | Maths
| Measurement
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Can somebody help me.i do not understand.
Date Posted: 5 years ago
Views: 301
The pattern repeats every 4 numbers.
4,0,1,2 4,0,1,2 4,0,1,2....
626 ÷ 4 = 156 R 2
So we know we have 156 sets of 4 numbers , and 2 numbers as remainder.
156 x 4 = 624
Every 4th number is a 2. Since 624 is a multiple of 4, the 624th number is 2.
So the 626th number must be 0
ii)
Realise that every 4 numbers add up to 7, as 4 + 0 + 1 + 2 = 7
We know that from i), 624 = 156 x 4.
So for the first 624 numbers, there are 156 sets of these 4 numbers.
So 156 x 7 = 1092
Now the 625th , 626th and 627th number are 4, 0 and 1 respectively.
So 1092 + 4 + 0 + 1 = 1097
4,0,1,2 4,0,1,2 4,0,1,2....
626 ÷ 4 = 156 R 2
So we know we have 156 sets of 4 numbers , and 2 numbers as remainder.
156 x 4 = 624
Every 4th number is a 2. Since 624 is a multiple of 4, the 624th number is 2.
So the 626th number must be 0
ii)
Realise that every 4 numbers add up to 7, as 4 + 0 + 1 + 2 = 7
We know that from i), 624 = 156 x 4.
So for the first 624 numbers, there are 156 sets of these 4 numbers.
So 156 x 7 = 1092
Now the 625th , 626th and 627th number are 4, 0 and 1 respectively.
So 1092 + 4 + 0 + 1 = 1097
See 1 Answer
done
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The 1st ans is o. The 2nd ans is 1097
Date Posted:
5 years ago
Hi Cher, your answers are correct.
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