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secondary 4 | A Maths
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How todo (ii)? Thank you.
Date Posted: 5 years ago
Views: 267
Instantaneously at rest means v = 0
Find what is t first.
To find acceleration, differentiate the expression. Then sub the value of t in
To find displacement, integrate the expression. Upper bound is the value of t you find above, lower bound is 0
Find what is t first.
To find acceleration, differentiate the expression. Then sub the value of t in
To find displacement, integrate the expression. Upper bound is the value of t you find above, lower bound is 0
Hi Sonia! I will write up the answers later when I return late at night.
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Hi Sonia! I'm so sorry for the delayed response. For part (ii), we need to obtain the value of t when the object is not moving before we find the displacement (integrate v dt) and acceleration (dv/dt) with the value of t found.
In this chapter, we need to realise that differentiating displacement gives velocity and differentiating velocity gives acceleration. The reverse processes are integration.
We also need to be able to distinguish between displacement and distance, as there is a difference between the two terms. If you are taking Physics as well, you would probably have learnt the difference between these two terms.
In this chapter, we need to realise that differentiating displacement gives velocity and differentiating velocity gives acceleration. The reverse processes are integration.
We also need to be able to distinguish between displacement and distance, as there is a difference between the two terms. If you are taking Physics as well, you would probably have learnt the difference between these two terms.
Date Posted:
5 years ago
Thankssss!!:)))
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