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secondary 4 | A Maths
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How to do Q2b?
Date Posted: 5 years ago
Views: 284
-2 < x < 4
=> (x+2)(x-4) < 0
=> x² + 2x - 4x - 8 < 0
=> x² - 2x - 8 < 0
=> 2x² - 4x - 16 < 0
=> a = -4 & b = -16
=> (x+2)(x-4) < 0
=> x² + 2x - 4x - 8 < 0
=> x² - 2x - 8 < 0
=> 2x² - 4x - 16 < 0
=> a = -4 & b = -16
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Date Posted:
5 years ago
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