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secondary 4 | E Maths
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I dont get how i can solve this ,please help
Date Posted: 5 years ago
Views: 377
BCD = 180° - 68° = 112° (opposite angles of a cyclic quadrilateral add up to 180°
Since BC = DC, BCD is isosceles. And CBD = CDB
So CDB = (180 - 112)° ÷ 2 = 34° (base angle of isosceles triangle)
CDB = BAC (angles in the same segment BC) = 34°
Since BC = DC, BCD is isosceles. And CBD = CDB
So CDB = (180 - 112)° ÷ 2 = 34° (base angle of isosceles triangle)
CDB = BAC (angles in the same segment BC) = 34°
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done
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You are on the right track already.
Date Posted:
5 years ago
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