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primary 5 | Maths
| Fractions
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Hi, how do I solve this problem with modelling? Thanks
ie add 4 more 2kg bags or take away 4 5kg bags.
Let's say i add 4 more 2kg bags (ie 'make the 2kg number of bags = 5kg bags"..... Therefore 4x2 = 8kg will be added. Total weight will then be 272 + 8 = 280kg.
Now, no. of 5kg bags = no. of 2kg bags, the weight of 1 group of bags = 5+2 = 7kg.
1 group of 7kg = 280
No. of groups = 280/7 = 40.
Total 80 bags but i added 4 bags to the 2kg, so actual = 80-4 = 76.
Can understand?
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Thanks
First model is for the number of bags, second model is for the masses.
By doing up the model for the masses, we can include the number 272.
There are an unknown mass of ‘7-kg’ bags (each 7-kg bag is equal to one 5-kg bag PLUS one 2-kg bag). With the extra 20 kg coming from the 4 extra bags, the total mass is 272 kg. It follows that the total mass of the ‘7-kg’ bags is 252 kg.
There must have been 36 of such '7-kg' bags to get 252 kg. This means that there are 36 of 5-kg bags and 36 of 2-kg bags.
Remember that there are 4 more 5-kg bags.
So the total is 36 + 36 + 4 = 76 bags.
So one large 7 kg bag is actually made up of TWO bags, one each of 5 kg and 2 kg.
You can check at the end that 40 bags of 5 kg each and 36 bags of 2 kg each gets you 272 kg altogether.
So 36 sets of 7kg bags means that there are 36 bags of 5kg AND 36 bags of 2kg.
So the number of bags is 36(7kg bags) and 36(2kg bags). But we cannot forget the extra 4 bags of 5kg.
So its 36+36+4=76.