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primary 6 | Maths
| Geometry
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Date Posted: 5 years ago
Views: 507
∡DCA = (180-64)/2 = 58° &
∡DCE = 180° - ∡DCA = 122°
∡ABC = 64°
∡BCA = (180-64)/2 = 58° &
∡ACB = 180° - ∡BCA = 122°
∡CDF = ∡DCA = 58°
or
∡DAC = ∡DCA = 58°
∡FEA + ∡DAC = 180°
∡FEA = 180 - 58 = 122°
∡FDA = ∡FEA = 122°
∡CDF + ∡CDA = 122°
∡CDF = 122-64 = 58°
∡DCE = 180° - ∡DCA = 122°
∡ABC = 64°
∡BCA = (180-64)/2 = 58° &
∡ACB = 180° - ∡BCA = 122°
∡CDF = ∡DCA = 58°
or
∡DAC = ∡DCA = 58°
∡FEA + ∡DAC = 180°
∡FEA = 180 - 58 = 122°
∡FDA = ∡FEA = 122°
∡CDF + ∡CDA = 122°
∡CDF = 122-64 = 58°
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solved in less then 2 mins. u can do it.
Date Posted:
5 years ago
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