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secondary 4 | A Maths
2 Answers Below
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hi im stuck
OP = 8,
so PQ = 6
coordinates of Q is (8, 6)
(ii)
OQ is diameter,
radius of circle is 2.5 units.
midpoint M of OQ is (4, 3)
which is centre of circle.
equation of circle:
(x - 4)² + (y - 3)² = (2.5)²
4(x - 4)² + 4(y - 3)² = 25
(2x - 8)² + (2y - 6)² = 25
OR
x² - 8x + 16 + y² - 6y + 9 - 6.25 = 0
x² - 8x + y² - 6y + 18.75 = 0
4x² - 32x + 4y² - 24y + 75 = 0
(iii)
if x-coordinate of R is 8,
which is directly above (or below) P,
(y-coordinate of R is unknown);
tan ∡ORP = tan 38°
RP = 10.24 units (n.a.)
as 10.24 units is more than 6 units,
which means R is above pt Q
OR
R is below pt P, which is outside the circle;
so x-coordinate of R is not equal to 8.
since R lies inside the circle (given),
then x-coordinate of R has to be less than 8.
From the way this part of the question is set,The setter probably intended for R to be inside the circle. it is likely that the value of 38° is more wrong than the phrasing.
For angle ORP, if R is ON the circle, it will be 53 degrees also. The closer R is to the centre, the greater the angle would be (by the properties of the circle); if R is the centre, then angle ORP would be 106 degrees.
It’s not possible for R to be inside the circle as a result.
See 2 Answers
R lie On the circle.
Is it question ask wrongly for
R inside the circle?