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primary 6 | Maths
| Fractions
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Date Posted: 5 years ago
Views: 337
Let number of kaya and red beans buns sold be 1u each.
Since ½ of red bean buns are left, ½ were sold.
½ of red bean buns = 1u
So total number of red bean buns = 2u
Since ¾ of kaya buns are left, ¼ was sold.
¼ of kaya buns = 1u
So total kaya buns = 4u
Total number of buns left = 3u + 1u = 4u
4u = 72
1u = 72 ÷ 4 = 18
Number of red beans at first = 2u
= 2 x 18
= 36
Since ½ of red bean buns are left, ½ were sold.
½ of red bean buns = 1u
So total number of red bean buns = 2u
Since ¾ of kaya buns are left, ¼ was sold.
¼ of kaya buns = 1u
So total kaya buns = 4u
Total number of buns left = 3u + 1u = 4u
4u = 72
1u = 72 ÷ 4 = 18
Number of red beans at first = 2u
= 2 x 18
= 36
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Date Posted:
5 years ago
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