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primary 6 | Maths
| Fractions
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Date Posted: 5 years ago
Views: 424
Let number of ties = 4u , wallets = 1u
4u ties cost $184 more than 1u wallets.
So $840 - $184 = $656
$656 ÷ 2 = $328
The wallets cost $328.
Cost of 4u ties = $328 + $184 = $512
So cost of 1u ties = $512 ÷ 4 = $128
We compare the costs of 1u wallets and 1u ties.
Difference in price = $328 - $128
= $200
Since one wallet costs $50 more than a tie,
$200 ÷ $50 = 4
So 4 wallets cost $200 more than 4 ties. This also tells you that 4 wallets were bought.
4u ties cost $184 more than 1u wallets.
So $840 - $184 = $656
$656 ÷ 2 = $328
The wallets cost $328.
Cost of 4u ties = $328 + $184 = $512
So cost of 1u ties = $512 ÷ 4 = $128
We compare the costs of 1u wallets and 1u ties.
Difference in price = $328 - $128
= $200
Since one wallet costs $50 more than a tie,
$200 ÷ $50 = 4
So 4 wallets cost $200 more than 4 ties. This also tells you that 4 wallets were bought.
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Hi Candy, I have uploaded steps by steps working of the above to YouTube https://youtu.be/q-OcA-kIbnY , you can learn from there.
Date Posted:
5 years ago
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