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Question
secondary 3 | A Maths
2 Answers Below
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STUCK!
Date Posted: 5 years ago
Views: 407
You will end up with 3a + 5b + ab√5 + 3√5
= (3a + 5b) + (ab + 3)√5
Compare the coefficients.
3a + 5b = 26
ab + 3 = 11
= (3a + 5b) + (ab + 3)√5
Compare the coefficients.
3a + 5b = 26
ab + 3 = 11
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done
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We need to expand everything and compare terms. You will face two equations involving a and b, of which you must solve them simultaneously.
Date Posted:
5 years ago
done
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I hope this solution helps you ! :)
Date Posted:
5 years ago
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