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secondary 3 | E Maths
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I cant figure out the working. Couldnt get the answer which is e<-10
Date Posted: 5 years ago
Views: 300
Multiply both sides by 12 first.
Hi J. Thx a lot. I managed to solve it.
Welcome. Trick is to get rid of the fractions by multiplying by a common multiple.
In this case, we multiply by the LCM of 4 (denominator of ¼), 3 (denominator of ⅔) and 6 (denominator of 1/6). The LCM of 4,3 and 6 is 12.
In this case, we multiply by the LCM of 4 (denominator of ¼), 3 (denominator of ⅔) and 6 (denominator of 1/6). The LCM of 4,3 and 6 is 12.
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done
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I hope this solution is able to help you !
Date Posted:
5 years ago
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