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First question

Date Posted:
1 month ago

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The chain rule is again to be used here. The first chain is the large bracket attached to the ln, because otherwise you would just be differentiating ln x, but instead it’s the ln of something else.

We can treat the derivative of the term in the large brackets as a separate bracket. There will be a chain rule element involved in differentiating the (x2 + 1)^0.5; the chain this time is (x^2 + 1), because we are otherwise simply differentiating x^0.5 easily.

We can treat the derivative of the term in the large brackets as a separate bracket. There will be a chain rule element involved in differentiating the (x2 + 1)^0.5; the chain this time is (x^2 + 1), because we are otherwise simply differentiating x^0.5 easily.

Date Posted:
1 month ago

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Where possible, we split the ln into different ln using the rules of logarithms. This facilitates easier differentiation.

Date Posted:
1 month ago

Thank You so much for your help.. I really appreicate it ....