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secondary 4 | E Maths

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How to do q4 !! Thanks for help in advance!!

= 90° + x°

OB = OC (both are radius of the same cir cle)

Since D is midpoint of BC,

BD = CD

OD is common to △BOD and △ COD

So △ BOD and △COD are congruent (SSS)

So ∠BOD = ∠ COD

∠COB = ∠COD + ∠COB

(90 + x)° = 2∠COD (since ∠BOD = ∠ COD)

∠COD = (90 + x)° ÷ 2

= (45 + ½x)°

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