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How do you find X?
Date Posted: 5 years ago
Views: 428
draw a horizontal line from E (to the right) that is parallel to AB, let the end pt be G.
so ∡AEG = 180 - ∡BAE = 62°
∡GEF = 87 - ∡AEG = 25°
next,
draw a horizontal line from F (to the left) that is parallel to AB, let the end pt be H.
so ∡EFH = ∡GEF = 25°
&
∡HFC = ∡DCF = 34°
hence,
∡CFE = ∡HFC + ∡EFH = 59°
therefore,
x° = 360° - 59° = 301°
& x = 301
so ∡AEG = 180 - ∡BAE = 62°
∡GEF = 87 - ∡AEG = 25°
next,
draw a horizontal line from F (to the left) that is parallel to AB, let the end pt be H.
so ∡EFH = ∡GEF = 25°
&
∡HFC = ∡DCF = 34°
hence,
∡CFE = ∡HFC + ∡EFH = 59°
therefore,
x° = 360° - 59° = 301°
& x = 301
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Hope this helps!
Date Posted:
5 years ago
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