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primary 6 | Maths
| Data Analysis
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Let G represent Gerald's money.
If Steven spent $50 dollars a day, while Gerald spent $25 a day, then Steven will have $100 when Gerald has $0.
Therefore, the number of days it will take Steven to run out of money is 2 more than the number of days it will take for Gerald to run out of money.
S/50 = G/25 + 2
If Steven spent $25 a day, while Gerald spent $50 a day, then Steven will have $400 while Gerald has $0.
Therefore, the number of days it will take Steven to run out of money is 16 more than the number of days it will take for Gerald to run out of money.
S/25 = G/50 + 16
Multiply both equations by 50:
S = 2G + 100
2S = G + 800
Multiply the first equation by 2:
2S = 4G + 200
Therefore, G + 800 = 4G + 200.
Rearrange:
3G = 600
Simplify:
G = 200
The amount of money Gerald have is $200.
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