 ## Question

primary 6 | Maths | Data Analysis

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##### Anonymous

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Pls help

Date Posted: 4 months ago
Views: 27
Edward Yang
4 months ago
Let S represent Steven's money.

Let G represent Gerald's money.

If Steven spent \$50 dollars a day, while Gerald spent \$25 a day, then Steven will have \$100 when Gerald has \$0.

Therefore, the number of days it will take Steven to run out of money is 2 more than the number of days it will take for Gerald to run out of money.

S/50 = G/25 + 2

If Steven spent \$25 a day, while Gerald spent \$50 a day, then Steven will have \$400 while Gerald has \$0.

Therefore, the number of days it will take Steven to run out of money is 16 more than the number of days it will take for Gerald to run out of money.

S/25 = G/50 + 16

Multiply both equations by 50:

S = 2G + 100

2S = G + 800

Multiply the first equation by 2:

2S = 4G + 200

Therefore, G + 800 = 4G + 200.

Rearrange:

3G = 600

Simplify:

G = 200

The amount of money Gerald have is \$200. 