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Secondary 1 | Maths
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qn b & c please !!
i need the answers before 5
Date Posted: 5 years ago
Views: 549
Let X be the unknown number.
HCF of X and 56: 8
LCM of X and 56: 504
Notice that X must be a multiple of 8.
The prime factorization of 504 is 2^3 * 3^2 * 7.
The prime factorization of 56 is 2^3 * 7.
Therefore, X must have the factor 3^2.
The least possible value of X is therefore 8 * 9 = 72.
The prime factorization of 117 is 3^2 * 13.
The prime factorization of 675 is 3 * 5^2 * 13.
The HCF of these 2 numbers is 3 * 13 = 39.
HCF of X and 56: 8
LCM of X and 56: 504
Notice that X must be a multiple of 8.
The prime factorization of 504 is 2^3 * 3^2 * 7.
The prime factorization of 56 is 2^3 * 7.
Therefore, X must have the factor 3^2.
The least possible value of X is therefore 8 * 9 = 72.
The prime factorization of 117 is 3^2 * 13.
The prime factorization of 675 is 3 * 5^2 * 13.
The HCF of these 2 numbers is 3 * 13 = 39.
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done
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clear
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Sorry if wrong
Date Posted:
5 years ago
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