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secondary 4 | E Maths
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Kathy
Kathy

secondary 4 chevron_right E Maths chevron_right Singapore

Thank you

Date Posted: 5 years ago
Views: 205
Han Zhi Yuan
Han Zhi Yuan
5 years ago
Let km represent kilometers.
Let h represent hours.

The car has an average speed of 600km/xh, while the plane has an average speed of 600km/(x - 11/2)h.

We know that the average speed of the plane is 220km/h faster than the car, so:

600km/xh + 220km/h = 600km/(x - 11/2)h

Let's remove the units to make it easier to expand out later:

600/x + 220 = 600/(x - 11/2)

Now, we multiplying both sides by x(x - 11/2):

600(x - 11/2) + 220x(x - 11/2) = 600x

Expand out:

600x - 3300 + 220x^2 - 1210x = 600x

We can remove "600x" from both sides:

220x^2 - 1210x - 3300 = 0

Dividing both sides by 110:

2x^2 - 11x - 30 = 0

Now, we factorise:

(2x - 15)(x + 2) = 0

x = 15/2 or x = -2

But since x is representing the number of hours, x = -2 is rejected.

The average speed of the car is therefore 600km/(15/2)h = 1200km/15h = 80km/h.

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
We need to convert the word problem into an equation using the relation

Distance = Speed x Time

and the other two modified expressions of the same equation for speed and time.

Remember that the value of x which we extract at the end must make sense i.e. x must be positive since x represents the time taken for the journey (even x = 0 does not really make much sense here).