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primary 6 | Maths
| Ratio
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Hi, appreciate if anyone could help, thank you.
Date Posted: 5 years ago
Views: 311
684 - 300 = 384 coins
So 384 coins were taken out.
384 = ⅔ of coins in L and ⅔ of coins in M (these coins were taken out)
So total coins in L and M = 384 x 3/2
= 576 coins
(You can also see this as :
384 = 2u of L and 2u of M
So total coins in L and M = 3u of L + 3u of M = 384 ÷ 2 x 3 = 576)
So, number of coins in K
= 684 - 576
= 108
Since ratio of coins in K to L
= 1 : 3,
Number of coins in container L
= 108 x 3
= 324
Therefore, number of coins in M
= 576 - 324
= 252
So 384 coins were taken out.
384 = ⅔ of coins in L and ⅔ of coins in M (these coins were taken out)
So total coins in L and M = 384 x 3/2
= 576 coins
(You can also see this as :
384 = 2u of L and 2u of M
So total coins in L and M = 3u of L + 3u of M = 384 ÷ 2 x 3 = 576)
So, number of coins in K
= 684 - 576
= 108
Since ratio of coins in K to L
= 1 : 3,
Number of coins in container L
= 108 x 3
= 324
Therefore, number of coins in M
= 576 - 324
= 252
Thank you very much!
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Hope this helps
Date Posted:
5 years ago
Thank you very much!
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