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Secondary 1 | Maths
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is the ans 64?
Date Posted: 5 years ago
Views: 284
29.05 x 86.61 = 2516.0205
78 x 29.9 = 2332.2
Space left over =
2516.0205 - 2332.2 = 183.8205
Since we need 400m² for gaps and pathways,
400 - 183.8205 = 216.1795
216.1795 m² more is required. So we have to remove some booths.
216.1795 ÷ 29.9 ≈ 7.23008361
You'll have to remove at least 8 booths.
78 - 8 = 70
78 x 29.9 = 2332.2
Space left over =
2516.0205 - 2332.2 = 183.8205
Since we need 400m² for gaps and pathways,
400 - 183.8205 = 216.1795
216.1795 m² more is required. So we have to remove some booths.
216.1795 ÷ 29.9 ≈ 7.23008361
You'll have to remove at least 8 booths.
78 - 8 = 70
I see what you mean, Eris. I did not account for the booths being cut up. J here indeed posted the right solution. To remove confusion, I deleted my answer below.
It's fine! Thanks for trying!
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