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primary 6 | Maths
| Fractions
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Date Posted: 5 years ago
Views: 335
Page 1 to 9 : 9 pages, 1 digit per page.
9 x 1 = 9
Page 10 to 99 :
number of pages = (99 - 9) = 90 pages
2 digits per page.
90 x 2 = 180
Total above = 180 + 9 = 189
Number of digits from the 3-digit pages
= 978 - 189 = 789 digits
789 ÷ 3 = 263
So there are 263 3-digit pages.
Since the first 3-digit page is page 100,and there are 263 3-digit pages, the last page of the book must be 262 pages later
→ 100 + 262 = 362
The last page is page 362 and therefore the book has 362 pages.
9 x 1 = 9
Page 10 to 99 :
number of pages = (99 - 9) = 90 pages
2 digits per page.
90 x 2 = 180
Total above = 180 + 9 = 189
Number of digits from the 3-digit pages
= 978 - 189 = 789 digits
789 ÷ 3 = 263
So there are 263 3-digit pages.
Since the first 3-digit page is page 100,and there are 263 3-digit pages, the last page of the book must be 262 pages later
→ 100 + 262 = 362
The last page is page 362 and therefore the book has 362 pages.
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Hope this helps.
Date Posted:
5 years ago
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