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Question
junior college 1 | H1 Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Thanks in advance
Date Posted: 5 years ago
Views: 339
y√(¼ - y²) = y(¼ - y²)^(½)
∫y(¼ - y²)^(½)
= (¼ - y²)^(½+1)/(2(½+1))
= ⅓(¼ - y²)^(3/2)
It is directly integrable. Sub the upper and lower limit accordingly
∫y(¼ - y²)^(½)
= (¼ - y²)^(½+1)/(2(½+1))
= ⅓(¼ - y²)^(3/2)
It is directly integrable. Sub the upper and lower limit accordingly
See 1 Answer
done
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clear
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I used the substitution y = 0.5 sin u so that I can get rid of the evil square root there (which is the "root" of why the function cannot be integrated easily).
Date Posted:
5 years ago
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