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Question
secondary 3 | A Maths
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Date Posted: 5 years ago
Views: 188
2^x = 3^y = 6^z
ln 2^x = ln 3^y = ln 6^z
xln2 = yln3 = zln6= z(ln2+ln3)
ln3/ln2 = y/x and z(ln2 + ln3) = xln2
z = xln2/(ln2 + ln3)
z = x/(1 + ln3/ln2)
z = x/(1 + y/x) = xy/(y + x)
ln 2^x = ln 3^y = ln 6^z
xln2 = yln3 = zln6= z(ln2+ln3)
ln3/ln2 = y/x and z(ln2 + ln3) = xln2
z = xln2/(ln2 + ln3)
z = x/(1 + ln3/ln2)
z = x/(1 + y/x) = xy/(y + x)
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Date Posted:
5 years ago
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