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secondary 3 | A Maths
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Only b
Date Posted: 5 years ago
Views: 203
(α - β)² = α² - 2αβ + β²
(α - β)² = α² + 2αβ + β² - 4αβ
(a - β)² = (α + β)² - 4αβ
(a - β) = √((α+β)² - 4αβ)
Only the positive answer is correct as α > β, so α - β > 0
(α - β)² = α² + 2αβ + β² - 4αβ
(a - β)² = (α + β)² - 4αβ
(a - β) = √((α+β)² - 4αβ)
Only the positive answer is correct as α > β, so α - β > 0
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