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These are the complete answers..Hope it is clear enough & helps your understanding of the application in this type of qn..
Date Posted:
5 years ago
For qn a part ii,its 180deg - 42deg-70.5deg=67.4616deg (angle HPQ)..
hi. your part c i i cant see
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Here's the whole of part c..It should be clear by now..
Date Posted:
5 years ago