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secondary 4 | A Maths
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rate of change
Date Posted: 5 years ago
Views: 464
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Hi qaz,
I believe the answer would be +/- 2.
Firstly,you have a careless mistake in your dy/dx. It should be 48/4x^2, not 24. You forgot to multiply the 2 into the 24.
Secondly, you're mostly on the right track actually. You just need to replace dx/dt with 3 dy/dt.
Then move the dy/dt from the RHS over to the LHS, which results in division of dy/dt, and it will disappear and give you the constant 3. With this you should be able to solve for p.
I believe the answer would be +/- 2.
Firstly,you have a careless mistake in your dy/dx. It should be 48/4x^2, not 24. You forgot to multiply the 2 into the 24.
Secondly, you're mostly on the right track actually. You just need to replace dx/dt with 3 dy/dt.
Then move the dy/dt from the RHS over to the LHS, which results in division of dy/dt, and it will disappear and give you the constant 3. With this you should be able to solve for p.
Date Posted:
5 years ago
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