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secondary 4 | A Maths
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mint
Mint

secondary 4 chevron_right A Maths chevron_right Singapore

please help , my answers not correct and not sure where went wrong :/

Date Posted: 5 years ago
Views: 303

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
Your dy/dx is perfectly fine.

When y = 0 (NOT when dy/dx = 0)

So 0 should be substituted into y, NOT dy/dx. Basically you want to find the values of x for which y = 0.

Then, for each of these values of x, we find the respective value of dy/dx.
Eric Nicholas K
Eric Nicholas K
5 years ago
Sorry, ignore the left side working, it's irrelevant to this question.