 Question

primary 6 | Maths | Data Analysis

Anyone can contribute an answer, even non-tutors.

chevron_right chevron_right chevron_right

Date Posted: 5 months ago
Views: 41

clear {{ downvoteCount * -1 }} Downvotes
Hope this helps! I solved it using simultaneous equations.
Date Posted: 5 months ago
clear {{ downvoteCount * -1 }} Downvotes
For this question, a good idea is to find a way to make the number of fish equal in both cases. This involves the lowest common multiple (LCM) of two numbers.

The LCM of 2 and 3 is equal to 6, so we express both cases in terms of 6 kg of fish.

If 3 kg mutton and 2 kg fish cost \$42, then three times the amount bought will cost three times as much, so 9 kg mutton and 6 kg fish cost \$126.

We do a very similar method for the other case and we see that 4 kg mutton and 6 kg fish cost \$83.

The only difference that separates the 9 kg mutton and 6 kg fish from the 4 kg mutton and 6 kg fish is the extra 5 kg of mutton which will cost an extra \$43.

From there, we can find the cost of 1 kg of mutton and then the cost of 1 kg of fish.
Date Posted: 5 months ago
Grace Goh
5 months ago 