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primary 6 | Maths | Data Analysis
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Grace Goh
Grace Goh

primary 6 chevron_right Maths chevron_right Data analysis chevron_right Singapore

Please help me. Thanks

Date Posted: 5 months ago
Views: 41

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Goh Sue Grace
Goh Sue Grace's answer
10 answers (Tutor Details)
1st
Hope this helps! I solved it using simultaneous equations.
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Eric Nicholas K
Eric Nicholas K's answer
2263 answers (Tutor Details)
For this question, a good idea is to find a way to make the number of fish equal in both cases. This involves the lowest common multiple (LCM) of two numbers.

The LCM of 2 and 3 is equal to 6, so we express both cases in terms of 6 kg of fish.

If 3 kg mutton and 2 kg fish cost $42, then three times the amount bought will cost three times as much, so 9 kg mutton and 6 kg fish cost $126.

We do a very similar method for the other case and we see that 4 kg mutton and 6 kg fish cost $83.

The only difference that separates the 9 kg mutton and 6 kg fish from the 4 kg mutton and 6 kg fish is the extra 5 kg of mutton which will cost an extra $43.

From there, we can find the cost of 1 kg of mutton and then the cost of 1 kg of fish.
Grace Goh
Grace Goh
5 months ago
Thanks alot for your help