Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
How do i solve this equation? Pls help!
Date Posted: 5 years ago
Views: 223
Let x = 2
Sub x = 2, → expression = 0
By the Factor Theorem, (x - 2) is a factor.
Let x = 3
Sub x = 3, → expression = 0
By the Factor Theorem, (x - 3) is a factor.
Let x = 4
Sub x = 4, → expression = 0
By the Factor Theorem, (x - 4) is a factor.
(x - 3)(x -2)(x - 4) = (x² - 5x + 6)(x - 4)
= x³ - 9x² + 26x - 24
Now 2x⁴ - 19x³ + 61x² - 74x + 24 = 0
Factorise :
(x³ - 9x² + 26x - 24)(2x - 1) = 0
So x = 3 or x = 2 or x = 4 or 2x - 1 = 0
→ or 2x = 1
x = ½
Sub x = 2, → expression = 0
By the Factor Theorem, (x - 2) is a factor.
Let x = 3
Sub x = 3, → expression = 0
By the Factor Theorem, (x - 3) is a factor.
Let x = 4
Sub x = 4, → expression = 0
By the Factor Theorem, (x - 4) is a factor.
(x - 3)(x -2)(x - 4) = (x² - 5x + 6)(x - 4)
= x³ - 9x² + 26x - 24
Now 2x⁴ - 19x³ + 61x² - 74x + 24 = 0
Factorise :
(x³ - 9x² + 26x - 24)(2x - 1) = 0
So x = 3 or x = 2 or x = 4 or 2x - 1 = 0
→ or 2x = 1
x = ½
Thank you
Yes i get it already thank you
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hope this helps u
Date Posted:
5 years ago
360 Tutoring Program