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secondary 3 | E Maths

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Can anyone help me with this qn?

Second thing to take note is that it's a base, so the lines DQ and CP are perpendicular to the base. That makes triangle DBQ a right angled triangle. You have the length DB, and

DQ = CP= 15. So again, you can use Pythagoras to get BQ.

B) Looking at the triangle BPC, it's a right angled triangle with lengths 22 and 15. If you have learned trigonometry, you can now find the angle PBC using the inverse tangent of the two sides. Remember, it's opposite over adjacent, meaning it's the inverse tangent of 15/22.

C) Much like part B, you can use trigonometry to find the angle DBQ. Only this time you have all three lengths of the triangle DBQ. Use any of the trigonometry rules to find the answer.

Give it a try. Hope it helps!!

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