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secondary 3 | E Maths
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Candy
Candy

secondary 3 chevron_right E Maths chevron_right Singapore

Can anyone help me with this qn?

Date Posted: 10 months ago
Views: 198
Muhd Ilman Fahmi
Muhd Ilman Fahmi
10 months ago
A) Take a look at the base rectangle ABCD. Two things to take note is that it's a rectangle, meaning the line BD cutting through the rectangle is a right angled triangle, since the corners of the rectangle are 90 degrees. Therefore using Pythagoras theorem, you can use the side lengths AB (29cm) and AD (22cm) to get the length DB, since ABD is a right angle triangle.

Second thing to take note is that it's a base, so the lines DQ and CP are perpendicular to the base. That makes triangle DBQ a right angled triangle. You have the length DB, and
DQ = CP= 15. So again, you can use Pythagoras to get BQ.

B) Looking at the triangle BPC, it's a right angled triangle with lengths 22 and 15. If you have learned trigonometry, you can now find the angle PBC using the inverse tangent of the two sides. Remember, it's opposite over adjacent, meaning it's the inverse tangent of 15/22.

C) Much like part B, you can use trigonometry to find the angle DBQ. Only this time you have all three lengths of the triangle DBQ. Use any of the trigonometry rules to find the answer.

Give it a try. Hope it helps!!
Candy
Candy
10 months ago
Thanks , i will try ! :)

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