## Question

Primary 3 | Maths

Anyone can contribute an answer, even non-tutors.

##### Amir

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Date Posted: 7 months ago
Views: 73
Amir
7 months ago
J
7 months ago
There is a problem with the phrasing of this question.

Other than the answer given by the other tutor, you could also pack them into 2 bags, with 19 sweets per bag.

19 sweets x 2 bags = 38 sweets
19 jellies x 2 bags = 38 sweets

Number of sweets left = 39 - 38 = 1
Number of jellies left = 48 - 38 = 10

Then the greatest number of sweets per bag would be 19 , not 3.
Amir
7 months ago
Thank you for your comments but shouldn’t the final answer be 13 being the highest number of sweets.
The common factor is 3 so take the number of sweets from the question which is 39 divided by 3 equals 13.
Derek Kua
7 months ago
True. Tutor J is right. The phrasing of the question is not clear, and we don’t know if it is literally asking for the greatest number of sweets that can be put into 2 or more bags (because bags - plural) or it is asking for the highest common factor of the sweets and jellies. It all depends on what the question is really asking for.
J
7 months ago
Hi Amir, that would be 3 bags, 13 sweets and 13 jellies in each bag. That would be a lower number per bag than the one I've suggested. Furthermore, 48 jellies ÷ 3 = 16 jellies per bag. That wouldn't give you the same number of jellies as sweets in each of the 3 bags.

You'll also have 9 jellies left over. Best is to consult your teacher on how to approach this question
J
7 months ago
Totally agree with you Tutor Derek!
Amir
7 months ago
Noted, thank you!