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How ro do c?? Tq
Date Posted: 6 years ago
Views: 397
I mean do... sorry typo error
From (a), possible values of p are 2 and -2.
From (b), possible values of q are 4 and - 4.
Since the range is 0 ≤ f(x) ≤ 6, h is positive as seen in the graph.
p has to be positive as the portion of the graph from 2 to h has a positive gradient.
q is negative as the straight line touches the negative part of the y axis when you extrapolate it from x = h to x = 0.
So p = 2, q = -4
Sub f(x) = 6, q = -4, p = 2, x = h into
f(x) = px + q :
6 = 2h - 4
2h = 10
h = 5
From (b), possible values of q are 4 and - 4.
Since the range is 0 ≤ f(x) ≤ 6, h is positive as seen in the graph.
p has to be positive as the portion of the graph from 2 to h has a positive gradient.
q is negative as the straight line touches the negative part of the y axis when you extrapolate it from x = h to x = 0.
So p = 2, q = -4
Sub f(x) = 6, q = -4, p = 2, x = h into
f(x) = px + q :
6 = 2h - 4
2h = 10
h = 5
See 1 Answer
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Use the graph given x and y to get p and q value , f(x)= - |2x+4| , then solve again by substitute 6 into f(x) , convert modulus into +- and you get the logic answer
Date Posted:
6 years ago
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