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junior college 1 | H1 Maths
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Need help with question 6!
Date Posted: 6 years ago
Views: 447
Certain vital information missing. Volume of solution not given.
1g/100ml = 1% m/v
9.681 x 10^(-3) M Mg2+
= 9.681 x 10^(-3) mol/l
= 9.681 x 10^(-4) mol/100ml
(Recall 1l = 1000ml. So to get /100ml, ÷10 which also means x10^(-1) )
= 9.681 x 10^(-4)mol x 24.305g/mol /100ml
= 0.0235296705 g/100ml
= 0.0235 % m/v (3s.f)
The volume of sample is not needed as the concentration is what we are finding. Volume is required if you are finding the total mass or number of mol of Mg2+
9.681 x 10^(-3) M Mg2+
= 9.681 x 10^(-3) mol/l
= 9.681 x 10^(-4) mol/100ml
(Recall 1l = 1000ml. So to get /100ml, ÷10 which also means x10^(-1) )
= 9.681 x 10^(-4)mol x 24.305g/mol /100ml
= 0.0235296705 g/100ml
= 0.0235 % m/v (3s.f)
The volume of sample is not needed as the concentration is what we are finding. Volume is required if you are finding the total mass or number of mol of Mg2+
See 1 Answer
done
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9.803*10^-3 * 24.305 you get answer for mass / volume , since 9.803*10^-3 is in mole
Date Posted:
6 years ago
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