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Question
primary 6 | Maths
| Geometry
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I managed to solve a but I cannot solve b
Date Posted: 5 years ago
Views: 379
Let the unshaded area in between B and C be X.
A - B - C = A + X - B - C - X
= (A + X) - (B+C+X)
Notice that B+C+X is just the area of the square - area of a quarter circle.
To find A+X,
First draw a line from the top left corner of the square to the bottom right corner (cutting across A),to get two triangles.
½ x area of (A+X) = area of one quarter circle - area of one triangle.
so A+X is just twice of that.
A - B - C = A + X - B - C - X
= (A + X) - (B+C+X)
Notice that B+C+X is just the area of the square - area of a quarter circle.
To find A+X,
First draw a line from the top left corner of the square to the bottom right corner (cutting across A),to get two triangles.
½ x area of (A+X) = area of one quarter circle - area of one triangle.
so A+X is just twice of that.
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Oops i didn't name e regions according to qn, so pls refer to pic in my solution.
Date Posted:
5 years ago
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