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secondary 3 | E Maths
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Hi, can someone give me solutions for 4a and 4c? Thanks
Date Posted: 5 years ago
Views: 307
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Given the fact that PA and PB are tangents to the circle, and that they intersect at point P, where OP is a straight line, we can see that triangles OBP and OAP are symmetric about the line OP. Hence length of BP = Length of AP, Angle BOP = Angle POA
Date Posted:
5 years ago
full justification:
angle OAP = angle OBP (tan perp radius)
OP = OP (common line)
OA = OB (radii)
Therefore triangle OBP is congruent to triangle OAP
Thus BP = AP = 14, angle AOP = angle BOP = 49 degree
angle OAP = angle OBP (tan perp radius)
OP = OP (common line)
OA = OB (radii)
Therefore triangle OBP is congruent to triangle OAP
Thus BP = AP = 14, angle AOP = angle BOP = 49 degree
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