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primary 5 | Maths
| Angles & Geometry
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Date Posted: 5 years ago
Views: 399
1) Given that:
6sweets + 10jellies = 6.80
2) So let's halve of the above:
3sweets + 5jellies = 3.40
3) Also given:
10sweets + 5jellies = 5.50
When 3) - 2)
There will be zero jellies left
Left 10sweets - 3sweets = 5.50 - 3.40
7sweets = 2.10
Hence, 1sweet = 2.10/7 = $0.30
6sweets + 10jellies = 6.80
2) So let's halve of the above:
3sweets + 5jellies = 3.40
3) Also given:
10sweets + 5jellies = 5.50
When 3) - 2)
There will be zero jellies left
Left 10sweets - 3sweets = 5.50 - 3.40
7sweets = 2.10
Hence, 1sweet = 2.10/7 = $0.30
See 3 Answers
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I am using substitution of algebraic expressions here.
Date Posted:
5 years ago
Dont understand algebra. Sorry but thank you for working out for me .
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Hope this helps.
Date Posted:
5 years ago
Hi, just wanted to say alternatively, we can consider finding 3 sweets and 5 jellies ($3.40) which leads to same answer
7 sweets 5.50 - 3.40 = 2.10
1 sweet 2.10/7 = 0.30
7 sweets 5.50 - 3.40 = 2.10
1 sweet 2.10/7 = 0.30
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Hope this helps
Date Posted:
5 years ago
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