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junior college 2 | H1 Maths
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Help Varsha! Anyone can contribute an answer, even non-tutors.
Hi how do you find this answer? I got 406 kj mol^-1 which is wrong. Help is much appreciated! Thanks:)
Date Posted: 6 years ago
Views: 552
You'll have to provide the enthalpy change of the conversion in order to solve this question
The enthalpy change is -196kj mol^-1
Then the answer should be 504kj mol -1.
SO2 + ½O2 → SO3
Enthalpy change
B.E (reactants) - B.E (products)
= 2 x B.E (S=O, for SO2) + ½B.E (O=O) - 3 x B.E (S=O, for SO3)
-196 = 2 x 534 + ½ x 496 - 3 x B.E (S=O, for SO3)
SO2 + ½O2 → SO3
Enthalpy change
B.E (reactants) - B.E (products)
= 2 x B.E (S=O, for SO2) + ½B.E (O=O) - 3 x B.E (S=O, for SO3)
-196 = 2 x 534 + ½ x 496 - 3 x B.E (S=O, for SO3)
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