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Question
primary 5 | Maths
| Rate & Ratio
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20¢ x 30 = 600¢
600¢ ÷ 50¢ = 12
So 30 twenty-cent coins were exchanged for 12 fifty-cent coins.
Ratio of fifty cent to twenty cent at
first = 4 : 5
Multiply this by the value of the coins,
4 x 50¢ : 5 x 20¢
= 200¢ : 100¢
Total = 300¢
Ratio at the end = 7 : 5
Multiply this by the value of the coins,
7 x 50¢ : 5 x 20¢
= 350 ¢ : 100 ¢
Total = 450¢
But we know that total value at the start and at the end is the same. So we have to make the total the same.
300¢ x 3 = 900¢
450¢ x 2 = 900¢
So we should multiply the starting ratio by
3, and the end ratio by 2.
Starting ratio x 3 → 4 x 3 : 5 x 3
= 12 : 15
End ratio x 2→ 7 x 2 : 5 x 2
= 14 : 10
Ratio of difference = 2 : 5
Remember that 30 twenty-cent coins were exchanged for 12 fifty-cent coins.
So, difference between starting and end number of 20¢ coins is 30. Difference between starting and end number of 50¢ coins is 12.
We need to change the ratio of difference.
So multiply by 6.
2 : 5 → x6 → 12 : 30
So this means our starting ratio and end ratio should also be multiplied by 6.
Starting → 12 : 15 → 72 : 90
End → 14 : 10 → 84 : 60
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