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secondary 4 | A Maths
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Qn 3b
Date Posted: 5 years ago
Views: 267
From a, you know k=3. For b, the only possible constant term is 17010 - (42/x^10)*(the term of x^(-10) of a). That works out to be 0. So there is no constant term in b.
Oops, i got k=-3 for part a
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done
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clear
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The key here is to find the terms that will multiply(expand) out to give terms that are independent of x.
Date Posted:
5 years ago
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