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hope this helps.
if u still hv any doubts, feel free to ask. :)
if u still hv any doubts, feel free to ask. :)
Date Posted:
5 years ago
How to get P2 = 3 x 10^5 ?
oh,
20 m of water has pressure of
P₂ = ρ g h
= 1000 x 10 x 20
= 200 000 Pa
= 2 x 10⁵ Pa
u add this liquid pressure of 2 x 10⁵ Pa to the atm pressure of 1 x 10⁵ Pa, u get 3 x 10⁵ Pa.
Remember: at bottom of lake, the air bubble experience atm pressure AND liquid pressure.
:)
20 m of water has pressure of
P₂ = ρ g h
= 1000 x 10 x 20
= 200 000 Pa
= 2 x 10⁵ Pa
u add this liquid pressure of 2 x 10⁵ Pa to the atm pressure of 1 x 10⁵ Pa, u get 3 x 10⁵ Pa.
Remember: at bottom of lake, the air bubble experience atm pressure AND liquid pressure.
:)
Oh okay! Understood. Thank you so much! :)
u r welcome!
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