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Question
primary 5 | Maths
| Whole Numbers
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Date Posted: 5 years ago
Views: 384
Let n represents the figure no.
No of circles = 4n-3
No of triangles = 4n^2
When n=9,
No of circles = 4(9)-3 = 33
No of triangles = 4(9^2)= 324
4n-3 = 113
4n = 116
n = 116/4 = 29
Therefore figure 29 has 113 circles.
No of circles = 4n-3
No of triangles = 4n^2
When n=9,
No of circles = 4(9)-3 = 33
No of triangles = 4(9^2)= 324
4n-3 = 113
4n = 116
n = 116/4 = 29
Therefore figure 29 has 113 circles.
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Date Posted:
5 years ago
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