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primary 6 | Maths
| Measurement
2 Answers Below
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Help in question A and B
Date Posted: 5 years ago
Views: 592
210/8 = 26 R2
Therefore he can sell a maximum of 26 packets.
Half the max packets = 13 packets
Total cost = $26
Therefore he can sell a maximum of 26 packets.
Half the max packets = 13 packets
Total cost = $26
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done
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Hope this helps
Date Posted:
5 years ago
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