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Question
primary 6 | Maths
| Measurement
2 Answers Below
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Anyone can assist? Thanks
Date Posted: 6 years ago
Views: 427
Step 1: Determine the common integers that are both divisible by 6 & 8.
Step 2: Divide the common integer by 10 to determine the remainder.
Step 3: Repeat for the next integer if the remainder is not 2. Continue until you get the correct ans. Take note the first correct integer is the smallest amount of stickers she have.
Step 2: Divide the common integer by 10 to determine the remainder.
Step 3: Repeat for the next integer if the remainder is not 2. Continue until you get the correct ans. Take note the first correct integer is the smallest amount of stickers she have.
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Answer is 72
10x7 is 70. And additional 2 leftover
72/6 is 12
72/8 is 9
10x7 is 70. And additional 2 leftover
72/6 is 12
72/8 is 9
Date Posted:
6 years ago
Don't really understand. Can explain further?
When divided by 10, there is 2 leftover. So 72 divided by 10, there’s 2 leftover.
72 can be divided by 6 and 8 with no leftover
72 can be divided by 6 and 8 with no leftover
How do you get 72 in first place?
You can do what I did by writing all the multiples of 6 and 8.
But I actually mental sums in my head. 2x10 +2 =22 and See if it can be divided by 6&8. And then 3x10+2 =32, etc. cause it’s easier to see from 10 and add a 2.
But I actually mental sums in my head. 2x10 +2 =22 and See if it can be divided by 6&8. And then 3x10+2 =32, etc. cause it’s easier to see from 10 and add a 2.
Thanks
The easiest way I feel is to see if 22 is divided by 6&8, then 32, 42,53,62,72,82,92. Since multiple of 10+ 2
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Since if she have 6 or 8 students it will be EQUAL, the numbers have to be a multiple of 6 and 8. Then after finding the similar number they have, divide by 10 students to see how many left they have.
Use trial and error.
Use trial and error.
Date Posted:
6 years ago
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