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secondary 4 | A Maths
2 Answers Below
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Can someone help me with this? I
have a feeling I should be doing the
b^2-4ac but I am not so sure on the sign....
Date Posted: 5 years ago
Views: 304
Hi. Can i just check with you first on the answer given? Thankyou
My teacher didn't give us the answer sheet sadly.
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done
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clear
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*Please note that my approach to this question might be wrong. Please do update me when your teacher goes through the answer.
Hope this helps! Please do help me double check if i made any careless mistakes. I have included some tips too which helped me answer this question. All the best!
Hope this helps! Please do help me double check if i made any careless mistakes. I have included some tips too which helped me answer this question. All the best!
Date Posted:
5 years ago
Sorry but your method does not work, I had the same thoughts and tried it.
This is a trick question ofc, they are tempting you to simply use the always negative for a ptv coeff. graph which would give you an error in working.
When you try to simply solve the quadratic double unknown inequality expression, you will end up with a bsquare- 4ac less than zero answer beside your inequality
Your approach is the same but also different..
This is a trick question ofc, they are tempting you to simply use the always negative for a ptv coeff. graph which would give you an error in working.
When you try to simply solve the quadratic double unknown inequality expression, you will end up with a bsquare- 4ac less than zero answer beside your inequality
Your approach is the same but also different..
@DH Kwon. I appreciate the prompt feedback. Can I see the other approach which i suppose you have tried?
*correction to my answer: a《-2 (rejected since a>0)
Just my two cents worth. Try a counter example. Let a=1 based on your answer, the graph of y=x^2 + x + 4 is always positive for all real values of x which is not what the question wants (less than or equal to zero)
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