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secondary 4 | E Maths
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question 6a(ii) please
Date Posted: 6 years ago
Views: 509
Seems you can solve 6a(i), so you know AQ. PQ is half EC, that is 15cm. so tan(PAQ)=15/AQ, you can find angel PAQ now
Use Pythagora's Theorem to get AQ.
AQ^2 = BQ^2 + AB^2
Get answer for AQ by square-root of both side of the equation
Since Q is mid-way of BC... PQ should be half the height of EC. 15cm height.
We now know Opposite and Adjacent. We should then apply Tangent ratio.
TAN (pAq) = Opp/Adjacent.
pAq = TAN^-1 (Opp/Adj)
AQ^2 = BQ^2 + AB^2
Get answer for AQ by square-root of both side of the equation
Since Q is mid-way of BC... PQ should be half the height of EC. 15cm height.
We now know Opposite and Adjacent. We should then apply Tangent ratio.
TAN (pAq) = Opp/Adjacent.
pAq = TAN^-1 (Opp/Adj)
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